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The Diagonals Of A Rhombus Are 16 And 30

Ex 6.5, 8 The diagonals of a rhombus measure 16 cm and 30 cm
Ex 6.5, 8 The diagonals of a rhombus measure 16 cm and 30 cm from www.teachoo.com

Welcome to our article that discusses the diagonals of a rhombus. In this article, we will be exploring the properties of a rhombus and how to calculate the length of its diagonals. If you are unfamiliar with the concept of a rhombus, it is a quadrilateral with four equal sides. The diagonals of a rhombus intersect at a 90-degree angle, and they bisect each other.

Properties of a Rhombus

Before we dive into the details of how to calculate the length of the diagonals of a rhombus, let's first explore some of the properties of a rhombus. As mentioned earlier, a rhombus is a quadrilateral with four equal sides. This means that all the sides of a rhombus are of equal length.

Another important property of a rhombus is that its opposite angles are equal. This means that if we label the angles of a rhombus as A, B, C, and D, then angle A is equal to angle C, and angle B is equal to angle D.

Furthermore, the diagonals of a rhombus bisect each other, which means that they divide each other into two equal parts. This also means that the length of one diagonal is equal to half the length of the other diagonal.

Calculating the Length of the Diagonals

Now that we have a basic understanding of the properties of a rhombus, let's move on to calculating the length of its diagonals. To calculate the length of the diagonals, we need to know the length of at least one of the diagonals.

In this case, we are given that one diagonal of the rhombus is 16 units in length. Let's label this diagonal as AC, and the other diagonal as BD. We know that the diagonals of a rhombus bisect each other, which means that the length of line segment AB is equal to the length of line segment CD.

Using the Pythagorean theorem, we can calculate the length of BD. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

Since we know that diagonal AC is 16 units in length, we can label half of AC as AD. Therefore, AD is equal to 8 units. We also know that the length of line segment AB is equal to the length of line segment CD. Let's label the length of AB as x.

Using the Pythagorean theorem, we can set up the following equation:

x^2 + 8^2 = BD^2

Simplifying this equation, we get:

x^2 + 64 = BD^2

Now, we need to find the value of x. We know that the length of one diagonal is equal to half the length of the other diagonal, so we can set up the following equation:

16 = (1/2)BD

Simplifying this equation, we get:

BD = 32

Substituting this value into our equation for BD^2, we get:

x^2 + 64 = 1024

Simplifying this equation, we get:

x^2 = 960

Taking the square root of both sides of the equation, we get:

x = 30.98

Therefore, the length of the other diagonal, BD, is approximately 32 units.

Conclusion

In conclusion, we have explored the properties of a rhombus and how to calculate the length of its diagonals. We have shown that given the length of one diagonal and the fact that the diagonals bisect each other, we can use the Pythagorean theorem to calculate the length of the other diagonal. In this case, we have calculated that the length of the diagonals of a rhombus with one diagonal of 16 units is approximately 16 and 32 units. We hope that this article has been helpful in understanding the concept of a rhombus and how to calculate the length of its diagonals.

Remember to always double-check your calculations and have fun exploring the wonderful world of geometry!

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